The angular velocity of the seconds hand of a | vedclass

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Question

(B) The angular velocity $\omega$ is defined as the rate of change of angular displacement $	heta$ with respect to time $t$,given by $\omega = \frac{

Vedclass · Accepted Answer

$\frac{\pi}{30} \ rad/s$

Vedclass · Answer

(B) The angular velocity $\omega$ is defined as the rate of change of angular displacement $	heta$ with respect to time $t$,given by $\omega = \frac{	heta}{t}$.For the seconds hand of a watch,it completes one full revolution,which corresponds to an angular displacement of $	heta = 2\pi \ rad$,in a time period of $t = 60 \ s$.Substituting these values into the formula:$\omega = \frac{2\pi}{60} \ rad/s = \frac{\pi}{30} \ rad/s$.

The angular velocity of the seconds hand of a watch will be:

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